/* * convert_ops.c * * Created on: Aug 27, 2011 * Author: Tiberiu */ #include const string _Numbers = "0123456789abcdefghijklmnopqrstuvwxyz"; int32 ConvertIntToString (string buffer, int32 number, int32 base) { if (base > 36 || base < 2) return 0; int32 len = numlen (number, base), beg = 0, i; uint32 n = (uint32) number; // If number is negative and in base 10, we put a '-' in front if (number < 0 && base == 10) buffer[beg++] = '-'; // Put every digit in string for (i = len-1; i>=beg; i--) { buffer[i] = _Numbers[n % base]; n /= base; } buffer[len] = 0; return number; } uint32 ConvertUIntToString (string buffer, uint32 number, int32 base) { if (base > 36 || base < 2) return 0; int32 len = unumlen (number, base), i; // Put every digit in string for (i = len-1; i >= 0; i--) { buffer[i] = _Numbers[number % base]; number /= base; } buffer[len] = 0; return number; } int32 ConvertStringToInt (string buffer) { int8 negative = (buffer[0] == '-'); int32 pos = (buffer[0] == '-' ); int32 number = 0; while (IsDigit(buffer[pos])) { number = number*10 + (buffer[pos] - '0'); pos++; } if (negative) return -number; return number; } uint32 ConvertStringToUInt (string buffer) { int32 pos = 0; int32 number = 0; while (IsDigit(buffer[pos])) { number = number*10 + (buffer[pos] - '0'); pos++; } return number; } uint32 ConvertStringToIntHex (string buffer) { int32 pos = 0; uint32 number = 0; // Skip first 2 digits if it is in format 0xXXXX... if (buffer[1] == 'x' || buffer[1] == 'X') pos = 2; while (IsHexDigit(buffer[pos])) { number = number*0x10; if (IsDigit(buffer[pos])) number += buffer[pos] - '0'; else if (buffer[pos] >= 'a' && buffer[pos] <= 'f') number += 10 + buffer[pos] - 'a'; else if (buffer[pos] >= 'A' && buffer[pos] <= 'F') number += 10 + buffer[pos] - 'A'; pos++; } return number; }